(27/8)/(3/4)^4*(9/4)^5=(2/3)^2n-1

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Solution for (27/8)/(3/4)^4*(9/4)^5=(2/3)^2n-1 equation: 


n in (-oo:+oo)

((27/8)/((3/4)^4))*(9/4)^5 = (2/3)^2*n-1 // - (2/3)^2*n-1

((27/8)/((3/4)^4))*(9/4)^5-((2/3)^2*n)+1 = 0

19715/32-4/9*n = 0 // - 19715/32

-4/9*n = -19715/32 // : -4/9

n = -19715/32/(-4/9)

n = 177435/128

n = 177435/128

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